If none of the digits 0, 1, 2, 3, 4 be repeated, how many numbers of five significant digits can be formed with them? How many of them are divisible by 4?
a) 96, 24
b) 72, 30
c) 96, 30
d) 72, 24
e) 72, 36
b) 72, 30
c) 96, 30
d) 72, 24
e) 72, 36
Answer & Explanation:
Part—(1) ®
5! – 4! = 96
Part–(2) ®
Last two digits can be 12, 20, 24, 32, 40
\ No. of nos. =
4+3!+4+4+3!= 24.
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