What is the probability that in a throw of two dice, the outcome will be a multiple of either 4 or 7?
Answer & Explanation:
The possible favorable outcomes must have sum of digits as
4, 8 or 7. Such outcomes are:
(1,3), (2,2),(3,1),
(2,6), (3,5), (4,4), (5,3), (6,2),
(1,6),(2,5), (3,4), (4,3), (5,2), (6,1)
The total number of such outcomes= 3+5+6= 14
Required probability= 14/36= 7/18.
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