QUESTION OF THE DAY:

Six boys and six girls sit along a line alternatively in x ways and along a circle again alternately in y ways, then
a) x = y 
b) y = 12x 
c) x = 10y
d) 16x = y
e) x = 12y

FOOD FOR THOUGHT:

QUESTION OF THE DAY:

The number of arrangements of the letters of the word BANANA in which the A’s do not appear adjacently is —

a) 40 
b) 48
c) 30
d) 32
e) 12

Answer and Explanation:

The different ways of arrangement are :
A __ A __ __ A arrangement = = 3 ways.
A __ A __ A __ arrangement = 3 ways.
__ A __ A __ A arrangement = 3 ways.
A __ __ A __ A arrangement = 3 ways.

So total of 12 ways.

FOOD FOR THOUGHT:

QUESTION OF THE DAY:

If none of the digits 0, 1, 2, 3, 4 be repeated, how many numbers of five significant digits can be formed with them? How many of them are divisible by 4?

a) 96, 24 
b) 72, 30
c) 96, 30
d) 72, 24
e) 72, 36

Answer & Explanation:

Part—(1) ® 5! – 4! = 96

Part–(2) ® Last two digits can be 12, 20, 24, 32, 40

                \ No. of nos. = 4+3!+4+4+3!= 24.

FOOD FOR THOUGHT:

QUESTION OF THE DAY:

What is the number of prime factors of 368?